Periodic Table Trends: Atomic Radius, Ionization Energy, and Electron Affinity Explained
By ChemistryIQ Team · March 19, 2026
Direct Answer
Periodic trends result from two competing forces: increasing nuclear charge (more protons pulling electrons inward) and increasing electron shielding (inner electrons blocking the pull of the nucleus). Across a period (left to right): atomic radius decreases, ionization energy increases, and electron affinity generally increases — because nuclear charge increases while electrons are added to the same shell (minimal additional shielding). Down a group (top to bottom): atomic radius increases, ionization energy decreases, and electron affinity generally decreases — because electrons are added to higher shells farther from the nucleus despite the increasing nuclear charge.
Atomic Radius: Size Across and Down
Atomic radius is the distance from the nucleus to the outermost electron cloud boundary. It follows two trends so consistently that you can predict relative sizes for almost any pair of elements.
Across a period (left to right), radius decreases. Why: each element in the same period adds one proton to the nucleus and one electron to the same valence shell. The additional proton increases the nuclear charge pulling all electrons closer. The additional electron in the same shell provides almost no extra shielding (electrons in the same shell barely shield each other). The net effect: stronger pull, same shielding = smaller atom. Sodium (Na, radius ~186 pm) is much larger than chlorine (Cl, radius ~99 pm) even though they are in the same period — chlorine has 6 more protons pulling the same shell inward.
Down a group (top to bottom), radius increases. Why: each element down adds an entirely new electron shell. The new shell is farther from the nucleus and is heavily shielded by all the inner shells. Even though the nuclear charge also increases, the shielding effect dominates. Lithium (Li, radius ~152 pm) is much smaller than cesium (Cs, radius ~265 pm) because cesium has 5 shells of electrons between its valence electrons and its nucleus.
Ionic radius follows related but distinct patterns. Cations (positive ions) are smaller than their parent atom because removing electrons reduces electron-electron repulsion and the remaining electrons are pulled closer. Anions (negative ions) are larger because adding electrons increases repulsion and the electron cloud expands. Na (186 pm) → Na⁺ (95 pm): dramatic shrinkage. Cl (99 pm) → Cl⁻ (181 pm): dramatic expansion. This is why Na⁺ and Cl⁻ are nearly the same size despite Na being twice the radius of Cl as neutral atoms.
Ionization Energy: How Hard Is It to Remove an Electron?
Ionization energy (IE) is the energy required to remove the outermost electron from a gaseous atom. Higher IE means the electron is held more tightly. The trends are essentially the mirror image of atomic radius trends — smaller atoms hold their electrons more tightly.
Across a period, IE increases. More protons pulling on the same-shell electrons means each electron is harder to remove. Sodium has an IE of 496 kJ/mol. Argon has an IE of 1,521 kJ/mol. The outer electron in argon is held more than 3x as tightly because argon has 7 more protons pulling on the same shell.
Down a group, IE decreases. The outermost electron is farther from the nucleus and more heavily shielded by inner shells, so it takes less energy to remove. Lithium: 520 kJ/mol. Cesium: 376 kJ/mol. Despite having 52 more protons, cesium's valence electron is easier to remove because it is much farther away and shielded by 4 inner shells.
The exceptions that exams test: Be (900) has a higher IE than B (801) even though B is to the right. Why: Be has a full 2s sublevel (2s²), which is unusually stable. Removing an electron from a full sublevel costs extra energy. B's outermost electron is in 2p, which is slightly easier to remove. Similarly, N (1,402) has a higher IE than O (1,314) because N has a half-filled 2p sublevel (2p³) — the extra stability of the half-filled set means removing one electron from N is harder than from O, where one 2p orbital is already paired.
ChemistryIQ tests these exceptions specifically because they reveal whether you understand the underlying principle or just memorized the overall trend.
Electron Affinity: How Much Does the Atom Want Another Electron?
Electron affinity (EA) is the energy change when an atom gains an electron to form an anion. A more negative (larger magnitude) EA means the atom releases more energy upon gaining an electron — it wants the electron more strongly. The trends parallel ionization energy but with more exceptions.
Across a period, EA generally becomes more negative (stronger attraction for additional electrons). Halogens have the most negative electron affinities because gaining one electron completes their valence shell (achieves noble gas configuration). Chlorine has an EA of -349 kJ/mol — it desperately wants one more electron. Sodium has an EA of -53 kJ/mol — adding an electron to a nearly empty shell is not particularly stabilizing.
Down a group, EA generally becomes less negative (weaker attraction). Fluorine should have the strongest EA in its group, but chlorine actually has a more negative EA (-349 vs -328 kJ/mol for fluorine). The reason: fluorine's electron cloud is so small and dense that adding another electron creates significant electron-electron repulsion in the tiny 2p orbitals. Chlorine's larger 3p orbitals accommodate the extra electron with less repulsion. This F vs Cl exception is one of the most commonly tested points in periodic trends.
Noble gases have near-zero or positive electron affinities — their valence shells are full, so adding an electron means starting a new, unstable shell. Alkaline earth metals (Be, Mg, Ca) and nitrogen-group elements at half-filled sublevels also have unusually low electron affinities because their stable electron configurations resist the addition of another electron.
The overall pattern: elements that are close to a stable configuration (full shell, full sublevel, or half-filled sublevel) have either very high ionization energies, very low electron affinities, or both — because the stable arrangement does not want to change.
Putting It All Together: The Two-Force Model
Every periodic trend comes from the same two competing forces: effective nuclear charge (Zeff, the net positive charge felt by the valence electrons after subtracting the shielding from inner electrons) and the principal energy level of the outermost electrons.
Across a period: Zeff increases (each new proton adds to the pull, but same-shell electrons barely shield each other). The increasing Zeff pulls electrons closer (smaller radius), holds them tighter (higher IE), and attracts new electrons more strongly (more negative EA). Everything converges toward smaller, tighter, more reactive-toward-gaining-electrons.
Down a group: the principal energy level increases (electrons are in higher, farther shells). Even though Zeff also increases somewhat, the distance and shielding effects dominate. Electrons are farther out (larger radius), held less tightly (lower IE), and the atom is less eager to attract new electrons (less negative EA).
If you can explain any trend by saying Zeff increases across a period so... or new shells are added down a group so..., you understand periodic trends at the explanatory level — not just the memorization level. That explanatory understanding is what exams test when they present unfamiliar elements or ask you to predict properties you have never seen tabulated.
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Common questions about periodic table trends
Fluorine's 2p orbitals are so small that adding a seventh electron (to form F⁻) creates significant electron-electron repulsion. Chlorine's larger 3p orbitals accommodate the extra electron with less repulsion, so the energy released upon gaining the electron is greater. This is one of the few exceptions where the trend does not follow the standard across-the-period pattern.
Think of it as nuclear charge winning across (everything gets smaller and tighter) and distance winning down (everything gets bigger and looser). Across: radius decreases, IE increases, EA increases. Down: radius increases, IE decreases, EA decreases. The exceptions (Be>B, N>O, F<Cl) all relate to the extra stability of full or half-filled sublevels.
Yes. ChemistryIQ generates comparison problems where you must rank elements by atomic radius, ionization energy, or electron affinity — including the exceptions that test real understanding versus memorization.